Answer by true blue anil for Probability of two specific cards to be in your...
If you want to use the "slot" method ($4$ groups of $13$ slots each), since the question says my hand (of $13$),$Pr = \dfrac{13}{52}\dfrac{12}{51} = \dfrac{1}{17}$[In your attempt, $\Large\frac14$ was...
View ArticleAnswer by Haris for Probability of two specific cards to be in your hand in a...
Here's an alternative approach.We arrange the $52$ cards in a row. You get the first $13$ cards. The next player gets the next $13$ and so on.The total number of arranging the cards is $52!$.For you to...
View ArticleProbability of two specific cards to be in your hand in a game of bridge
Assume that a 52-card deck is distributed among 4 players, each with 13.What is the probability that two specific cards, say the Ace of Hearts and Ace of Diamonds to be in my hand?I have two approach...
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